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Sequences, Series & Telescoping Sums ​

Overview

A sequence {an} is a function from N→R (or C). A series is the sequence of partial sums Sn=∑k=1nak. In competitive mathematics, mastery lies in transforming unfamiliar summations into known algebraic identities, geometric series, or telescoping cancellations.


1. Classical Progressions Summary ​

📊Visual Mathematical Intuition
Infinite Geometric Series Dissection & Telescoping Cascade
1/2 1/4 1/8 1/16 Total Area = 1/2 + 1/4 + 1/8 + ... = 1 Telescoping Cancellation Ladder: T_1 = V_1 - V_0 T_2 = V_2 - V_1 T_3 = V_3 - V_2 ⋮ T_n = V_n - V_{n-1} S_n = V_n - V_0 (Internal Terms Cancel)
Infinite Sum:S∞=∑k=1∞(12)k=1/21−1/2=1S_\infty = \sum_{k=1}^\infty \left(\frac{1}{2}\right)^k = \frac{1/2}{1 - 1/2} = 1
Telescoping Ladder:∑k=1n(Vk−Vk−1)=Vn−V0\sum_{k=1}^n (V_k - V_{k-1}) = V_n - V_0

Visual unit-square dissection demonstrating ∑k=1∞(1/2)k=1\sum_{k=1}^\infty (1/2)^k = 1, alongside the telescoping cascade ladder collapsing Sn=Vn−V0S_n = V_n - V_0.

Arithmetic Progression (AP) ​

  • General term: an=a+(n−1)d
  • Sum of n terms: Sn=n2[2a+(n−1)d]=n2(a+l)

Geometric Progression (GP) ​

  • General term: an=arn−1
  • Sum of n terms: Sn=a(1−rn)1−r (r≠1)
  • Sum of infinite GP (|r|<1): S∞=a1−r

Arithmetic-Geometric Progression (AGP) ​

General AGP: S=a+(a+d)r+(a+2d)r2+⋯+(a+(n−1)d)rn−1

  • Sum of infinite AGP (|r|<1):S∞=a1−r+dr(1−r)2

2. The Vn−Vn−1 Telescoping Method ​

Fundamental Telescoping Identity

If the general term Tr of a series can be decomposed as Tr=Vr−Vr−1, then:

Sn=∑r=1nTr=(V1−V0)+(V2−V1)+⋯+(Vn−Vn−1)=Vn−V0

Type I: Factors in Denominator (Equally Spaced Factors) ​

Tr=1r(r+1)(r+2)…(r+k)

Multiply and divide by the difference of outermost factors (r+k)−r=k:

Tr=1k[1r(r+1)…(r+k−1)−1(r+1)(r+2)…(r+k)]=Vr−1−Vr∑r=1∞Tr=1k⋅1⋅2…k

Type II: Factors in Numerator ​

Tr=r(r+1)(r+2)…(r+k)=1k+2[r(r+1)…(r+k)(r+k+1)−(r−1)r(r+1)…(r+k)]Sn=n(n+1)(n+2)…(n+k+1)k+2

3. Standard Sigma Sum Formulas ​

∑k=1nk=n(n+1)2,∑k=1nk2=n(n+1)(2n+1)6,∑k=1nk3=[n(n+1)2]2

4. Double Summations ∑∑ ​

For independent summations over a grid 1≤i≤n,1≤j≤n:

∑i=1n∑j=1naiaj=(∑i=1nai)(∑j=1naj)=(∑i=1nai)2

For summations over 1≤i<j≤n:

∑1≤i<j≤naiaj=12[(∑i=1nai)2−∑i=1nai2]