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Sequences, Series & Telescoping Sums

Overview

A sequence {an} is a function from NR (or C). A series is the sequence of partial sums Sn=k=1nak. In competitive mathematics, mastery lies in transforming unfamiliar summations into known algebraic identities, geometric series, or telescoping cancellations.


1. Classical Progressions Summary

📊Visual Mathematical Intuition
Infinite Geometric Series Dissection & Telescoping Cascade
1/2 1/4 1/8 1/16 Total Area = 1/2 + 1/4 + 1/8 + ... = 1 Telescoping Cancellation Ladder: T_1 = V_1 - V_0 T_2 = V_2 - V_1 T_3 = V_3 - V_2 T_n = V_n - V_{n-1} S_n = V_n - V_0 (Internal Terms Cancel)
Infinite Sum:S=k=1(12)k=1/211/2=1S_\infty = \sum_{k=1}^\infty \left(\frac{1}{2}\right)^k = \frac{1/2}{1 - 1/2} = 1
Telescoping Ladder:k=1n(VkVk1)=VnV0\sum_{k=1}^n (V_k - V_{k-1}) = V_n - V_0

Visual unit-square dissection demonstrating k=1(1/2)k=1\sum_{k=1}^\infty (1/2)^k = 1, alongside the telescoping cascade ladder collapsing Sn=VnV0S_n = V_n - V_0.

Arithmetic Progression (AP)

  • General term: an=a+(n1)d
  • Sum of n terms: Sn=n2[2a+(n1)d]=n2(a+l)

Geometric Progression (GP)

  • General term: an=arn1
  • Sum of n terms: Sn=a(1rn)1r (r1)
  • Sum of infinite GP (|r|<1): S=a1r

Arithmetic-Geometric Progression (AGP)

General AGP: S=a+(a+d)r+(a+2d)r2++(a+(n1)d)rn1

  • Sum of infinite AGP (|r|<1):S=a1r+dr(1r)2

2. The VnVn1 Telescoping Method

Fundamental Telescoping Identity

If the general term Tr of a series can be decomposed as Tr=VrVr1, then:

Sn=r=1nTr=(V1V0)+(V2V1)++(VnVn1)=VnV0

Type I: Factors in Denominator (Equally Spaced Factors)

Tr=1r(r+1)(r+2)(r+k)

Multiply and divide by the difference of outermost factors (r+k)r=k:

Tr=1k[1r(r+1)(r+k1)1(r+1)(r+2)(r+k)]=Vr1Vrr=1Tr=1k12k

Type II: Factors in Numerator

Tr=r(r+1)(r+2)(r+k)=1k+2[r(r+1)(r+k)(r+k+1)(r1)r(r+1)(r+k)]Sn=n(n+1)(n+2)(n+k+1)k+2

3. Standard Sigma Sum Formulas

k=1nk=n(n+1)2,k=1nk2=n(n+1)(2n+1)6,k=1nk3=[n(n+1)2]2

4. Double Summations

For independent summations over a grid 1in,1jn:

i=1nj=1naiaj=(i=1nai)(j=1naj)=(i=1nai)2

For summations over 1i<jn:

1i<jnaiaj=12[(i=1nai)2i=1nai2]